Contributor: Mason Smith. Lesson ID: 11310
How well do you understand probability using multiple events? It all DEPENDS on how you complete this lesson! Learn about dependent and independent events with online practice and some observations!
Q: What do you call two unrelated activities scheduled on July 4th?
A: Independent events.
So far in this Probability: An Overview series, found under Related Lessons in the right-hand sidebar, we have covered experimental and theoretical probability.
However, the probability we have covered so far has only been for one single event.
This is where we have to take into account the idea of dependency, or how each event influences the other.
Of course not! It doesn't matter what you roll, you will still have the same probability of pulling an ace from a deck. This is the idea of independent events, when the first event does not have an effect on the probability of the other event.
The other form of dependency is a dependent event, when the first event affects the probability of the second event.
It is no longer 4/52, since there are not 52 cards in the deck (we already took one out); so the probability of the second card being an ace is 4⁄51.
Classify the following two events as either independent or dependent. Be sure to understand your reasoning:
You flip a penny, then flip a nickel to get heads.
Your sister selects a Monopoly piece from the 8 available, then you pick one from the remaining.
When we are working with dependent events, we can construct a tree diagram to keep track of the possibilities.
Below is an example of a tree diagram for flipping a coin twice.
When we calculate this, we want to work from left to right. So, if we are trying to find the probability of getting {HT}, then we multiply ½ (the probability for heads the first time which is on the "branch") times ½ (probability of tails the second time) to get the probability of {HH}, which is ¼.
This leads to an important formula for independent events:
So, the probability of both A and B happening is the product of each event.
Let's try this out with an example:
P(blue, yellow) = P(blue) * P(yellow) | = | 7 | + | 3 | = | 21 | |||
10 | 10 | 100 |
There are 8 results, with 4 odd results, so the probability of spinning an odd once is ½. It is independent because the first spin has no effect on the second.
P(2 odd numbers) | = | 1 | * | 1 | = | 1 | |||
2 | 2 | 4 |
Now that we know how to calculate independent events, let's try calculating dependent probability. Remember, with independent events, the probability does not change, but for dependent events, the probability will change from the first event to the second.
The formula for dependent events looks like this:
P(A and B) = P(A) * P(B after A)
However, that doesn't make much sense just looking at it, so let's try it with an example:
Well, since we do not replace the marble, these two events are dependent events. The probability of selecting a blue is pretty easy, so we can set up our formula like this:
P(Blue, Yellow) = P(Blue) * P(Y after B)
But, what is P(Y after B)? That is the probability of pulling a yellow, after we have already removed a blue, which means our probability is:
P(Y after B) | = | # of yellow | = | 6 |
# of total results after removing one | 9 |
Now, we can solve for the probability of pulling a blue then a yellow rather easily. Give it a try, then look at the correct result.
P(Blue, Yellow) | = | 4 | * | 6 | = | 24 | = | 12 | |||
10 | 9 | 90 | 45 |
Now that you have learned about the idea of dependency, independent, and dependent events, it is time to practice your new skills.